bjoernager/rust
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Remove -Zreport-delayed-bugs.

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It's not used within the repository in any way (e.g. in tests), and
doesn't seem useful.
This commit is contained in:
Nicholas Nethercote 2024-01-04 17:16:07 +11:00
parent e51e98dde6
commit cf9484e615
4 changed files with 3 additions and 17 deletions
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16
compiler/rustc_errors/src/lib.rs
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@ -525,9 +525,6 @@ pub struct DiagCtxtFlags {
/// If true, immediately emit diagnostics that would otherwise be buffered.
/// (rustc: see `-Z dont-buffer-diagnostics` and `-Z treat-err-as-bug`)
pub dont_buffer_diagnostics: bool,
/// If true, immediately print bugs registered with `span_delayed_bug`.
/// (rustc: see `-Z report-delayed-bugs`)
pub report_delayed_bugs: bool,
/// Show macro backtraces.
/// (rustc: see `-Z macro-backtrace`)
pub macro_backtrace: bool,
@ -1004,7 +1001,6 @@ impl DiagCtxt {
) -> ErrorGuaranteed {
let treat_next_err_as_bug = self.inner.borrow().treat_next_err_as_bug();
if treat_next_err_as_bug {
// FIXME: don't abort here if report_delayed_bugs is off
self.span_bug(sp, msg);
}
let mut diagnostic = Diagnostic::new(DelayedBug, msg);
@ -1016,11 +1012,7 @@ impl DiagCtxt {
// where the explanation of what "good path" is (also, it should be renamed).
pub fn good_path_delayed_bug(&self, msg: impl Into<DiagnosticMessage>) {
let mut inner = self.inner.borrow_mut();
let mut diagnostic = Diagnostic::new(DelayedBug, msg);
if inner.flags.report_delayed_bugs {
inner.emit_diagnostic_without_consuming(&mut diagnostic);
}
let diagnostic = Diagnostic::new(DelayedBug, msg);
let backtrace = std::backtrace::Backtrace::capture();
inner.good_path_delayed_bugs.push(DelayedDiagnostic::with_backtrace(diagnostic, backtrace));
}
@ -1430,10 +1422,8 @@ impl DiagCtxtInner {
self.span_delayed_bugs
.push(DelayedDiagnostic::with_backtrace(diagnostic.clone(), backtrace));
if !self.flags.report_delayed_bugs {
#[allow(deprecated)]
return Some(ErrorGuaranteed::unchecked_claim_error_was_emitted());
}
#[allow(deprecated)]
return Some(ErrorGuaranteed::unchecked_claim_error_was_emitted());
}
if diagnostic.has_future_breakage() {