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rustc: Don't translate the expression twice when adapting a borrowed method receiver. Closes #3357.

Adds a test case. I had to stare at this one for a bit.
This commit is contained in:
Patrick Walton 2012-09-02 16:50:00 -07:00
parent 49c9ac175f
commit b808cfbb74
3 changed files with 20 additions and 1 deletions

View file

@ -3151,6 +3151,9 @@ fn trans_arg_expr(cx: block, arg: ty::arg, lldestty: TypeRef, e: @ast::expr,
// routine consults this table and performs these adaptations. It returns a
// new location for the borrowed result as well as a new type for the argument
// that reflects the borrowed value and not the original.
//
// NB: "e" has already been translated; do not translate it again. If you do,
// this will cause problems with autoderef and method receivers (bug #3357).
fn adapt_borrowed_value(lv: lval_result,
e: @ast::expr,
e_ty: ty::t) -> {lv: lval_result,
@ -3200,7 +3203,7 @@ fn adapt_borrowed_value(lv: lval_result,
_ => {
// Just take a reference. This is basically like trans_addr_of.
let mut {bcx, val, kind} = trans_temp_lval(bcx, e);
let mut {bcx, val, kind} = lv;
let is_immediate = ty::type_is_immediate(e_ty);
if (kind == lv_temporary && is_immediate) || kind == lv_owned_imm {
val = do_spill(bcx, val, e_ty);

View file

@ -183,6 +183,7 @@ struct lookup {
match ty::deref(self.tcx(), self.self_ty, false) {
None => break,
Some(mt) => {
debug!("(checking method) ... autodereffing");
self.self_ty = mt.ty;
self.derefs += 1u;
}

View file

@ -0,0 +1,15 @@
struct Foo {
x: int;
}
impl Foo {
fn f(&self) {}
}
fn g(x: &mut Foo) {
x.f();
}
fn main() {
}