make relate
's const ty assertion use semantic equality
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7 changed files with 237 additions and 22 deletions
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@ -31,6 +31,7 @@ use super::{InferCtxt, MiscVariable, TypeTrace};
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use crate::traits::{Obligation, PredicateObligations};
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use rustc_data_structures::sso::SsoHashMap;
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use rustc_hir::def_id::DefId;
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use rustc_middle::infer::canonical::OriginalQueryValues;
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use rustc_middle::infer::unify_key::{ConstVarValue, ConstVariableValue};
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use rustc_middle::infer::unify_key::{ConstVariableOrigin, ConstVariableOriginKind};
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use rustc_middle::traits::ObligationCause;
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@ -152,6 +153,33 @@ impl<'tcx> InferCtxt<'tcx> {
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let a = self.shallow_resolve(a);
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let b = self.shallow_resolve(b);
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// We should never have to relate the `ty` field on `Const` as it is checked elsewhere that consts have the
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// correct type for the generic param they are an argument for. However there have been a number of cases
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// historically where asserting that the types are equal has found bugs in the compiler so this is valuable
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// to check even if it is a bit nasty impl wise :(
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//
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// This probe is probably not strictly necessary but it seems better to be safe and not accidentally find
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// ourselves with a check to find bugs being required for code to compile because it made inference progress.
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self.probe(|_| {
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if a.ty() == b.ty() {
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return;
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}
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// We don't have access to trait solving machinery in `rustc_infer` so the logic for determining if the
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// two const param's types are able to be equal has to go through a canonical query with the actual logic
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// in `rustc_trait_selection`.
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let canonical = self.canonicalize_query(
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(relation.param_env(), a.ty(), b.ty()),
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&mut OriginalQueryValues::default(),
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);
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if let Err(()) = self.tcx.check_const_param_definitely_unequal(canonical) {
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self.tcx.sess.delay_span_bug(
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DUMMY_SP,
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&format!("cannot relate consts of different types (a={:?}, b={:?})", a, b,),
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);
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}
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});
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match (a.kind(), b.kind()) {
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(
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ty::ConstKind::Infer(InferConst::Var(a_vid)),
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