Recover from X<Y,Z> when parsing const expr

This adds recovery when in array type syntax user writes

    [X; Y<Z, ...>]

instead of

    [X; Y::<Z, ...>]

Fixes #82566

Note that whenever we parse an expression and know that the next token
cannot be `,`, we should be calling
check_mistyped_turbofish_with_multiple_type_params for this recovery.
Previously we only did this for statement parsing (e.g. `let x = f<a,
b>;`). We now also do it when parsing the length field in array type
syntax.
This commit is contained in:
Ömer Sinan Ağacan 2021-02-27 13:37:50 +03:00
parent fb631a55c2
commit 992b914b6b
5 changed files with 79 additions and 5 deletions

View file

@ -360,12 +360,20 @@ impl<'a> Parser<'a> {
}
Err(err) => return Err(err),
};
let ty = if self.eat(&token::Semi) {
TyKind::Array(elt_ty, self.parse_anon_const_expr()?)
let mut length = self.parse_anon_const_expr()?;
if let Err(e) = self.expect(&token::CloseDelim(token::Bracket)) {
// Try to recover from `X<Y, ...>` when `X::<Y, ...>` works
self.check_mistyped_turbofish_with_multiple_type_params(e, &mut length.value)?;
self.expect(&token::CloseDelim(token::Bracket))?;
}
TyKind::Array(elt_ty, length)
} else {
self.expect(&token::CloseDelim(token::Bracket))?;
TyKind::Slice(elt_ty)
};
self.expect(&token::CloseDelim(token::Bracket))?;
Ok(ty)
}