bjoernager/rust
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Use Symbol equality in is_ident_named.

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This commit is contained in:
Nicholas Nethercote 2019-05-23 15:31:43 +10:00
parent 303bf1509b
commit 8ae01a9008
4 changed files with 10 additions and 8 deletions
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6
src/libsyntax/parse/parser.rs
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@ -2759,7 +2759,7 @@ impl<'a> Parser<'a> {
let (span, e) = self.interpolated_or_expr_span(e)?;
(lo.to(span), ExprKind::Box(e))
}
token::Ident(..) if self.token.is_ident_named("not") => {
token::Ident(..) if self.token.is_ident_named(sym::not) => {
// `not` is just an ordinary identifier in Rust-the-language,
// but as `rustc`-the-compiler, we can issue clever diagnostics
// for confused users who really want to say `!`
@ -4592,7 +4592,7 @@ impl<'a> Parser<'a> {
let do_not_suggest_help =
self.token.is_keyword(kw::In) || self.token == token::Colon;
if self.token.is_ident_named("and") {
if self.token.is_ident_named(sym::and) {
e.span_suggestion_short(
self.span,
"use `&&` instead of `and` for the boolean operator",
@ -4600,7 +4600,7 @@ impl<'a> Parser<'a> {
Applicability::MaybeIncorrect,
);
}
if self.token.is_ident_named("or") {
if self.token.is_ident_named(sym::or) {
e.span_suggestion_short(
self.span,
"use `||` instead of `or` for the boolean operator",