Add documentation
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@ -81,3 +81,56 @@ let ResultsTable;
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* }}
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*/
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let Results;
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/**
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* A pair of [inputs, outputs], or 0 for null. This is gets stored in the search index.
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* The JavaScript deserializes this into FunctionSearchType.
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*
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* An input or output can be encoded as just a number if there is only one of them, AND
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* it has no generics. The no generics rule exists to avoid ambiguity: imagine if you had
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* a function with a single output, and that output had a single generic:
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*
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* fn something() -> Result<usize, usize>
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*
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* If output was allowed to be any RawFunctionType, it would look like this
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*
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* [[], [50, [3, 3]]]
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*
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* The problem is that the above output could be interpreted as either a type with ID 50 and two
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* generics, or it could be interpreted as a pair of types, the first one with ID 50 and the second
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* with ID 3 and a single generic parameter that is also ID 3. We avoid this ambiguity by choosing
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* in favor of the pair of types interpretation. This is why the `(number|Array<RawFunctionType>)`
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* is used instead of `(RawFunctionType|Array<RawFunctionType>)`.
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*
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* @typedef {(
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* 0 |
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* [(number|Array<RawFunctionType>)] |
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* [(number|Array<RawFunctionType>), (number|Array<RawFunctionType>)]
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* )}
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*/
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let RawFunctionSearchType;
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/**
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* A single function input or output type. This is either a single path ID, or a pair of
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* [path ID, generics].
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*
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* @typedef {number | [number, Array<RawFunctionType>]}
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*/
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let RawFunctionType;
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/**
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* @typedef {{
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* inputs: Array<FunctionType>,
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* outputs: Array<FunctionType>,
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* }}
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*/
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let FunctionSearchType;
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/**
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* @typedef {{
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* name: (null|string),
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* ty: (null|number),
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* generics: Array<FunctionType>,
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* }}
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*/
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let FunctionType;
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