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libsyntax: Remove the use foo = bar syntax from the language in favor

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of `use bar as foo`.

Change all uses of `use foo = bar` to `use bar as foo`.

Implements RFC #47.

Closes #16461.

[breaking-change]
This commit is contained in:
Patrick Walton 2014-08-18 08:29:44 -07:00
parent 7074592ee1
commit 67deb2e65e
62 changed files with 140 additions and 136 deletions
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5
src/libsyntax/parse/parser.rs
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@ -5385,7 +5385,6 @@ impl<'a> Parser<'a> {
match self.token {
token::EQ => {
// x = foo::bar
// NOTE(stage0, #16461, pcwalton): Deprecate after snapshot.
self.bump();
let path_lo = self.span.lo;
path = vec!(self.parse_ident());
@ -5394,8 +5393,10 @@ impl<'a> Parser<'a> {
let id = self.parse_ident();
path.push(id);
}
let span = mk_sp(path_lo, self.span.hi);
self.obsolete(span, ObsoleteImportRenaming);
let path = ast::Path {
span: mk_sp(path_lo, self.span.hi),
span: span,
global: false,
segments: path.move_iter().map(|identifier| {
ast::PathSegment {