Implement AsRef<[T]>
for std::slice::Iter
.
`AsRef` is designed for conversions that are "cheap" (as per the API docs). It is the case that retrieving the underlying data of `std::slice::Iter` is cheap. In my opinion, there's no ambiguity about what slice data will be returned, otherwise, I would be more cautious about implementing `AsRef`.
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@ -645,6 +645,15 @@ fn test_iter_size_hints() {
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assert_eq!(xs.iter_mut().size_hint(), (5, Some(5)));
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}
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#[test]
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fn test_iter_as_ref() {
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let xs = [1, 2, 5, 10, 11];
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let mut iter = xs.iter();
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assert_eq!(iter.as_ref(), &[1, 2, 5, 10, 11]);
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iter.next();
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assert_eq!(iter.as_ref(), &[2, 5, 10, 11]);
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}
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#[test]
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fn test_iter_clone() {
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let xs = [1, 2, 5];
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@ -37,6 +37,7 @@ use clone::Clone;
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use cmp::{Ordering, PartialEq, PartialOrd, Eq, Ord};
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use cmp::Ordering::{Less, Equal, Greater};
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use cmp;
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use convert::AsRef;
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use default::Default;
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use fmt;
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use intrinsics::assume;
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@ -996,6 +997,13 @@ impl<'a, T> Clone for Iter<'a, T> {
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fn clone(&self) -> Iter<'a, T> { Iter { ptr: self.ptr, end: self.end, _marker: self._marker } }
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}
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#[stable(feature = "slice_iter_as_ref", since = "1.12.0")]
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impl<'a, T> AsRef<[T]> for Iter<'a, T> {
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fn as_ref(&self) -> &[T] {
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self.as_slice()
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}
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}
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/// Mutable slice iterator.
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///
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/// This struct is created by the [`iter_mut`] method on [slices].
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