bjoernager/rust
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Rename Ty::Literal as Ty::Path.

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Because a `Literal` is a type of expression, and is simply the wrong
name for this.
This commit is contained in:
Nicholas Nethercote 2022-06-30 10:20:19 +10:00
parent 18fef6bbd7
commit 00307a5b6f
9 changed files with 18 additions and 29 deletions
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6
compiler/rustc_builtin_macros/src/deriving/generic/ty.rs
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@ -77,7 +77,7 @@ pub enum Ty {
Ref(Box<Ty>, ast::Mutability),
/// `mod::mod::Type<[lifetime], [Params...]>`, including a plain type
/// parameter, and things like `i32`
Literal(Path),
Path(Path),
/// includes unit
Tuple(Vec<Ty>),
}
@ -103,7 +103,7 @@ impl Ty {
let raw_ty = ty.to_ty(cx, span, self_ty, self_generics);
cx.ty_rptr(span, raw_ty, None, *mutbl)
}
Literal(p) => p.to_ty(cx, span, self_ty, self_generics),
Path(p) => p.to_ty(cx, span, self_ty, self_generics),
Self_ => cx.ty_path(self.to_path(cx, span, self_ty, self_generics)),
Tuple(fields) => {
let ty = ast::TyKind::Tup(
@ -141,7 +141,7 @@ impl Ty {
cx.path_all(span, false, vec![self_ty], params)
}
Literal(ref p) => p.to_path(cx, span, self_ty, generics),
Path(ref p) => p.to_path(cx, span, self_ty, generics),
Ref(..) => cx.span_bug(span, "ref in a path in generic `derive`"),
Tuple(..) => cx.span_bug(span, "tuple in a path in generic `derive`"),
}